Question

can someone pls solve this
$[3a^{2} - 6ab - 3b^{2} + 1] - x = 4a^{2} - 7ab - 4b^{2} + 1$

Answer 1

Answer:

$\implies x=-a^{2}+ab + b^{2}$

Explanation:

$[3a^{2} - 6ab - 3b^{2} + 1] - x = 4a^{2} - 7ab - 4b^{2} + 1$

$\implies [3a^{2} - 6ab - 3b^{2} + 1] - 4a^{2} +7ab + 4b^{2} - 1= x$

$\implies [(3-4)a^{2}+( - 6+7)ab +(- 3+4)b^{2}] + 1 - 1= x$

$\implies -a^{2}+ab + b^{2} = x$

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