Can someone pls tell me what is dis questions answer
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in triangle ade and bce
we have
ad=bc
de=ce
angle ade =angle bce [90°+60°=150°]
hence triangle ade is congruent to triangle bce so,
angle dae=angle cbe (by cpct)
angle dab =angle cba = 90°
angle dae +angle eab =angle cbe angle eba
we have proved above that
angle dae=angle cbe
so,
angle eab = angle eba
therefore
ea = be [ opposite side of equal angle ]
2
we have
ad=bc
de=ce
angle ade =angle bce [90°+60°=150°]
hence triangle ade is congruent to triangle bce so,
angle dae=angle cbe (by cpct)
angle dab =angle cba = 90°
angle dae +angle eab =angle cbe angle eba
we have proved above that
angle dae=angle cbe
so,
angle eab = angle eba
therefore
ea = be [ opposite side of equal angle ]
2
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