Math, asked by bebokjp, 1 month ago

Can someone plz give me answer to this question..​

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Answers

Answered by barnwalarchanapckktb
1

Step-by-step explanation:

tan^2@ / (sec@ - 1)^2

sec^2@ - 1 / (sec@ - 1)^2

(sec@ - 1 )( sec@ + 1)/ (sec@ - 1)^2

sec@ + 1 / sec@ - 1

sec@ = 1/cos@

1 + cos@ / cos@ x cos@/ 1 - cos@

1 + cos@/ 1 - cos@

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