can someone plz send me the pictures of class X book ICSE...Chapter "Moment of Force"and " work power energy"....... plzzzzzz
Answers
Answer:
yes of course.......
..I am giving
Explanation:
(d)False
(e)False
Chapter 1 - Force Exercise Ex. 1A
Question 1
State the condition when on applying a force, the body has:
(a)the translational motion,
(b)the rotational motion.
Solution 1
(a)When the body is free to move it produces translational motion.
(b)When the body is pivoted at a point, it produces rotational motion.
Question 2
The moment of a force about a given axis depends:
(a) Only on the magnitude of force
(b) Only on the perpendicular distance of force from the axis
(c) Neither on the force nor on the perpendicular distance of force from the axis
(d) Both on the force and its perpendicular distance from the axis.
Solution 2
The moment of a force about a given axis depends on both on the force and its perpendicular distance from the axis.
Hint: Moment of force = Force x Perpendicular distance
Question 3
The moment of a force of 10N about a fixed point O is 5Nm. Calculate the distance of the point O from the line of action of the force.
Solution 3
Moment of force= force x perpendicular distance of force from point O
Moment of force= F x r
5Nm= 10 x r
R= 5/10 =0.5 m
Question 4
Define moment of force and state its S.I. unit.
Solution 4
The moment of force is equal to the product of the magnitude of the force and the perpendicular distance of the line of action of force from the axis of rotation.
S.I. unit of moment of force is Newton metre (Nm).
Question 5
A body is acted upon by two unequal forces in opposite directions, but not in same line. The effect is that
(a) The body will have only the rotational motion
(b) The body will have only the translational motion
(c) The body will have neither the rotational motion nor the translational motion
(d) The body will have rotational as well as translational motion.
Solution 5
The body will have rotational as well as translational motion.
Question 6
A nut is opened by a wrench of length 10cm. If the least force required is 5.0N, find the moment of force needed to turn the nut.
Solution 6
Length, r=10cm =0.1m
F= 5N
Moment of force= F x r= 5 x 0.1= 0.5 Nm
Question 7
State whether the moment of force is a scalar or vector quantity?
Solution 7
Moment of a force is a vector.
Question 8
A wheel of diameter 2m is shown with axle at O. A force F = 2N is applied at B in the direction shown in figure. Calculate the moment of force about (i) the centre O, and (ii) the point A.
Solution 8
Given , F= 2N
Diameter=2m
Perpendicular distance between B and O =1m
(i)Moment of force at point O
= F x r
=2 x 1=2Nm (clockwise)
(ii)Moment of force at point A= F x r
=2 x 2=4Nm (clockwise)
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