Physics, asked by aparnasharma12305, 5 months ago

can someone plz solve this question in detail..​

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Answered by somebody12370
1

Consider the following equations of a projectile with angle 

of projection θ and initial velocity v0 - here 

x=voxt refer to book ; 

rearrange the expression for time  t ,

 t=v0xx

substituted voxx for in the expression 

y=(v0sinθ)t−21gt2

  y=voy(voxx)−21g(v0xx)2

substitute vocosθ  for voxsin θ   for voy

in the above expression. 

Y=(v0sinθ)(vocosθx)−21g(vocosθx)2

 Hence the obtained equation of the projectile is 

Y=(tanθ

mark me brainliest!

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