can someone plz solve this question in detail..
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Consider the following equations of a projectile with angle
of projection θ and initial velocity v0 - here
x=voxt refer to book ;
rearrange the expression for time t ,
t=v0xx
substituted voxx for in the expression
y=(v0sinθ)t−21gt2
y=voy(voxx)−21g(v0xx)2
substitute vocosθ for voxsin θ for voy
in the above expression.
Y=(v0sinθ)(vocosθx)−21g(vocosθx)2
Hence the obtained equation of the projectile is
Y=(tanθ
mark me brainliest!
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