Chemistry, asked by patelsakera, 11 months ago

can someone share a CBSE class 11 physics papers.
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Answers

Answered by brokenheart4
1

❤❤HERE IS YOUR ANSWER ❤❤

The number of significant figures in 0.06900 is(a) 5(b) 4(c) 2(d) 3The sum of the numbers 436.32, 227.2 and 0.301 in appropriate significant figures is(a) 663.821(b) 664(c) 663.8(d) 663.82The mass and volume of a body are 4.237 g and 2.5 cm3, respectively. The density of the material of the body in correct significant figures is(a) 1.6048 g cm-3(b) 1.69 g cm-3(c) 1.7 g cm-3(d) 1.695 g cm-3The numbers 2.745 and 2.735 on rounding off to 3 significant figures will give(a) 2.75 and 2.74(b) 2.74 and 2.73(c) 2.75 and 2.73(d) 2.74 and 2.74The length and breadth of a rectangular sheet are 16.2 cm and 10.1cm, respectively. The area of the sheet in appropriate significant figures and error is(a) 164 ± 3 cm2(b) 163.62 ± 2.6 cm2(c) 163.6 ± 2.6 cm2(d) 163.62 ± 3 cm2Which of the following pairs of physical quantities does not have same dimensional formula?(a) Work and torque.(b) Angular momentum and Planck’s constant.(c) Tension and surface tension.(d) Impulse and linear momentum.Measure of two quantities along with the precision of respective measuring instrument is A = 2.5 m s-1 ± 0.5 ms-1 B = 0.10 s ± 0.01 s

The value of A B will be(a) (0.25 ± 0.08) m(b) (0.25 ± 0.5) m(c) (0.25 ± 0.05) m(d) (0.25 ± 0.135) mYou measure two quantities as A = 1.0 m ± 0.2 m, B = 2.0 m ± 0.2 m. We should report correct value for √ABas:(a) 1.4 m ± 0.4 m(b) 1.41m ± 0.15 m(c) 1.4m ± 0.3 m(d) 1.4m ± 0.2 m

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Answered by Anonymous
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