can someone solve and prove this is equal to (2sintheta)/ (1+tantheta)
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Answer:
Step-by-step explanation:
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Answer: 2 sin theta / 1 + tan theta
Step-by-step explanation:
2 sin theta x tan theta (1-tan theta) + 2sin theta x sec^2 theta
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(1 + tan theta)^2
= 2 sin theta (tan theta - tan^2 theta +sec^2 theta)
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(1 + tan theta)^2
= 2 sin theta ( tan theta - tan^ theta + 1 + tan^2 theta)
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(1 + tan theta)^2
Formula used above
-> ( sec^2 theta = 1 + tan^2 theta)
Hence,
= 2 sin theta (tan theta + 1)
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(1 + tan theta)^2
= 2 sin theta
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1 + tan theta
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