Question

can someone solve no. iv in copy and send me the photo​

Answer 1

The given equation is,    kx(x − 25√) + 10 = 0⇒kx2 − 25√kx + 10 = 0We geta = k, b = −25√k, c = 10Now, D = b2−4ac = (−25√k)2 − 4(k)(10) = 20k2 − 40kFor equal roots, D = 0⇒20k2 − 40k= 0⇒20k(k−2) = 0⇒k = 0 (rejected)  

kx2 - 2kx (2 root5)+ 10 = 0 
D = 0
b2 - 4ac = 0
= {- 2k(2 root5)}​2 - 4 (10)k = 0
= 20 * 4k2 - 40k = 0
= 80k2 - 40k = 0
= 2k2 - k = 0
= 2k - 1 = 0
= 2k = 1
= k = 1/2

Answer 2

Please mark as brainliest.