Question

Can someone solve the 12th question???

Answer 1

Answer:

$\frac{ \sqrt{2} + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } = \frac{( \sqrt{2} + \sqrt{3})(3 \sqrt{2} + 2 \sqrt{3} ) }{ {(3 \sqrt{2} )}^{2} - {(2 \sqrt{3}) }^{2} } \\ \\ = \frac{6 + 2 \sqrt{6} + 3 \sqrt{6} + 6 }{18 - 12} \\ \\ = \frac{12 + 5 \sqrt{6} }{6} \\ \\ = 2 + \frac{5}{6} \sqrt{6} \\ \\ compare \: = > x = 2 \: \: and \: \:Y= \frac{5}{6}$

Answer 2

Answer:

x=2 Or y=5/6

Step-by-step explanation:

=>√2+√3/3√2-2√3×3√2+2√3/3√2+2√3

=>(√2+√3)(3√2+2√3)/(3√2)^2-(2√3)^2

=>6+2√6+3√6+6/9×2-4×3

=>12+5√6/18-12

12+5√6/6

12/6+5√6/6

2+5√6/6

So x=2 and y=5/6