Question

can someone solve the above questions....
pls answer only if u know
invalid answers will be reported
need answers urgently
correct and valid answers will be marked brainliest and voted 5 stars​

Answer 1

Answer:

Step-by-step explanation:

a) ∠ABE=∠BCE +∠ABC=180°

   ∠ABE=55° + ∠ABC=180°

   ∠ABC=180 - 55 = 125°

   ∠ABC +  ∠AOC = 180°                      (opp. angles in a cyclic quad.)

   ∠AOC = 180° - ∠ABC= 180-125 =55°

   x + ∠AOC= 360°

  x = 360 - 55 = 305°

b) ∠QPR=30°

∴ ∠QSR=30                                        (angles subtended y same chord)

similarly, ∠SQR=∠SPR=70°                  (angles subtended y same chord)

inΔQRS, 70 + 30 +∠QRS=180

   ∠QRS=180-100=80°

really sorry but i don't know the further calculations please pardon me:((

c) ∠ADC=120

  ∠ADC + ∠ABC =180                            (sum of opp. angles in a cyclic quad.)

 ∠ABC=180 - 120 = 60

 ∠ABE= ∠ABC +x =180

x= 180 - 60 = 120

d) ∠POQ = 110

    ∠PRQ=∠POQ/2=110/2=55                  (angle subtended by a chord on centre is double the angle subtended by it in the circle)

hope this helps:)