Math, asked by bubu7sounak, 11 months ago

can someone solve the second one
im granting 50 points
pls help

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Answered by shreyadubey86
1

Answer:

2) first we removes the brackets by using a suitable formula:

Step-by-step explanation:

=12(2x-3y)^2+36(4x^2-9y^2)+27(2x+3y)^2

=12(4x^2+9y^2-12xy)+36(4x^2-9y^2)+27(4x^2+9y^2+12xy)

=48x^2+108y^2-144xy+144x^2-324y^2+108x^2+243y^2+324xy

=300x^2+27y^2+180xy

=3(100x^2+9y^2+60xy)

Answered by singhrupeshrupesh1
3

Answer:

hope the above helps u,thanku

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