Question

can someone solve this problem​

Answer 1

Answer:

3x-4y+12=0 ........1

3x+5y-15=0.........2

3x-4y=-12

3x+5y=15

subtract 2 by 1

3x+ 5y=15

3x-4y=-12

___________

0+9y=27

y=27÷9

y=3

putting the value of y in 2

we get

3x+5y=15

3x+5×3=15

3x=15-15

x=0÷3

x=0

solution set=x,y=0,3

P=0,3