Physics, asked by steph25, 1 year ago

can someone solve this? Q32

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Answered by MOSFET01
2
∆ Initial Potential Energy = m × g × h

=> 75 × 25 × 9.8

=> 18375

=> 1.83 × 10^4 Joules

{B}

∆ Potential energy 15 m above ground

=> 75 × 15 × 9.8

=> 11025

=> 1.10 × 10^4 Joules

{C}

∆ Maximum values of its K.E.

=> Max K.E. = Max P.E.
{by law of conservation of energy}

Max. KE = 1.83 × 10^4 Joules

{D}

∆ K.E. 20 m below the top of tower(or 15 m above ground )

=> Total energy - P.E. at the point

=> 1.83 × 10^4 - 1.10 × 10^4

=> 0.73 × 10^4 => 7.3 × 10^3 Joules

MOSFET01: @ stephs answer in your notes are mistake please check it
steph25: i know
steph25: thats why i asked this question
steph25: i got the same answers as did
steph25: as you did*
MOSFET01: okay then share it to your sir
MOSFET01: okay friend
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