can someone solve this? Q32
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∆ Initial Potential Energy = m × g × h
=> 75 × 25 × 9.8
=> 18375
=> 1.83 × 10^4 Joules
{B}
∆ Potential energy 15 m above ground
=> 75 × 15 × 9.8
=> 11025
=> 1.10 × 10^4 Joules
{C}
∆ Maximum values of its K.E.
=> Max K.E. = Max P.E.
{by law of conservation of energy}
Max. KE = 1.83 × 10^4 Joules
{D}
∆ K.E. 20 m below the top of tower(or 15 m above ground )
=> Total energy - P.E. at the point
=> 1.83 × 10^4 - 1.10 × 10^4
=> 0.73 × 10^4 => 7.3 × 10^3 Joules
=> 75 × 25 × 9.8
=> 18375
=> 1.83 × 10^4 Joules
{B}
∆ Potential energy 15 m above ground
=> 75 × 15 × 9.8
=> 11025
=> 1.10 × 10^4 Joules
{C}
∆ Maximum values of its K.E.
=> Max K.E. = Max P.E.
{by law of conservation of energy}
Max. KE = 1.83 × 10^4 Joules
{D}
∆ K.E. 20 m below the top of tower(or 15 m above ground )
=> Total energy - P.E. at the point
=> 1.83 × 10^4 - 1.10 × 10^4
=> 0.73 × 10^4 => 7.3 × 10^3 Joules
MOSFET01:
@ stephs answer in your notes are mistake please check it
i know
thats why i asked this question
i got the same answers as did
as you did*
okay then share it to your sir
okay friend
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