Question

Can someone tell me Formulas of Surface area and Volume Class 10

Answer 1

Hey matr!!!!!!!!


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Answer-:
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☛ CUBOID:-
(1) VOLUME OF CUBOID = L×B×H
(2) CSA OF CUBOID= 2(L+B)×H
(3) TSA OF CUBOID= 2(LB+BH+LH)

☛ CUBE:-
(1) VOLUME OF CUBE = A³
(2) CSA OF CUBE= 4A²
(3) TSA OF CUBE = 6A²

☛ CYLINDER:-
(1) VOLUME OF CYLINDER= πR²H
(2) CSA OF CYLINDER= 2πRH
(3) TSA OF CYLINDER= 2πR(H+R)

☛ CONE:-
(1) VOLUME OF CONE = 1/3πR2H
(2) CSA OF CONE = πRL
(3) TSA OF CONE = πRL +πR² = πR(L+R)

☛ SPHERE:-
(1) VOLUME OF SPHERE = 4/3πR³
(2) TSA OF SPHERE = 6A²

☛ HEMISPHERE :-
(1) VOLUME OF HEMISPHERE = 2/3πR³
(2) CSA OF HEMISPHERE = 2A²
(3) TSA OF HEMISPHERE = 3A².

☛ FRUSTUM OF CONE:-
(1) VOLUME = R²+r²+ Rr
(2) CSA = πL(R+r)²

Answer 2

Surface area of cuboid=2(lb+bh+hl)

Surface area of cube=6a²

Curved surface area of cylinder=2πrh

Total surface area of cylinder=2πr(r+h)

Curved surface area of cone=I'll

Total surface area of cone=πr(l+r)

Surface area of sphere. 4πr²

Curved surface area of hemisphere.2πr²

Total surface area of hemisphere.3πr²

Volume of cuboid.l.b.h

Volume of a cube.a³

Volume of a cylinder.πr²h

Volume of a cone.1/3πr²h

Volume of a sphere 4/3πr³

Volume of a hemisphere.2/3πr³...

Curved surface area of frustum of cone.πl(r+R)

Volume of frustum of cone.1/3πh(r²+R²+rR)

Total surface area of frustum of cone.πl(r+R)+π(r²+R²)

I hope it will help you more...

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