can someone tell me what is binomial theorem ?
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have two polynomials in a equation and first like x is the digree two called bionomial and two veritable also
eg 2xsquare+4x +2 square is non as bionomial
I hope helpfull for you....
Binomial theorem, statement that for any positive integer n, the nth power of the sum of two numbers a and b may be expressed as the sum of n + 1 terms of the form
Equation.
in the sequence of terms, the index r takes on the successive values 0, 1, 2,…, n. The coefficients, called the binomial coefficients, are defined by the formula
Equation.
in which n! (called n factorial) is the product of the first n natural numbers 1, 2, 3,…, n (and where 0! is defined as equal to 1). The coefficients may also be found in the array often called Pascal’s triangle
Representation of the array called Pascal's triangle.
by finding the rth entry of the nth row (counting begins with a zero in both directions). Each entry in the interior of Pascal’s triangle is the sum of the two entries above it. Thus, the powers of (a + b)n are 1, for n = 0; a + b, for n = 1; a2 + 2ab + b2, for n = 2; a3 + 3a2b + 3ab2 + b3, for n = 3; a4 + 4a3b + 6a2b2 + 4ab3 + b4, for n = 4, and so on
eg 2xsquare+4x +2 square is non as bionomial
I hope helpfull for you....
Binomial theorem, statement that for any positive integer n, the nth power of the sum of two numbers a and b may be expressed as the sum of n + 1 terms of the form
Equation.
in the sequence of terms, the index r takes on the successive values 0, 1, 2,…, n. The coefficients, called the binomial coefficients, are defined by the formula
Equation.
in which n! (called n factorial) is the product of the first n natural numbers 1, 2, 3,…, n (and where 0! is defined as equal to 1). The coefficients may also be found in the array often called Pascal’s triangle
Representation of the array called Pascal's triangle.
by finding the rth entry of the nth row (counting begins with a zero in both directions). Each entry in the interior of Pascal’s triangle is the sum of the two entries above it. Thus, the powers of (a + b)n are 1, for n = 0; a + b, for n = 1; a2 + 2ab + b2, for n = 2; a3 + 3a2b + 3ab2 + b3, for n = 3; a4 + 4a3b + 6a2b2 + 4ab3 + b4, for n = 4, and so on
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yar inasked binomial theorem
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