Question

can someone work out this maths problem for me
ILL mark u as brainliest and also provide you with 100 points

Answer 1

Answer:

Given: Radius of inner circle =7 cm

Radius of outer circle =14 cm

Angle made by sector = 40o

Area of sector OAC = 360o40o×πr2

=91××722×142=68.44

Area of sector OBD = 360o40o×πr2

=91××722×72=17.11

Area of the small region ABDC

= Area of the small sector OAC – Area of the small sector OBD =(68.44−17.11)cm2

Area of shaded region ABDC= Area of outer circle  −  Area of inner circle − area of small region ABCD

Area of shaded region ABDC=π×142−π×72−(68.44−17.11)cm2 

Area of shaded region ABDC=410.484 cm

Step-by-step explanation:

please give me some thanks

make me brainlist