Math, asked by lxaryan, 1 year ago

can't find the solution please help

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Answered by Anonymous
1
I m right or m I right
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Answered by kushanaanandp4ac8a
0
LHS
(tanA-cotA)/sinAcosA.
=tanA/sinAcosA - cotA/sinAcosA.
=(sinA/cosA)/sinAcosA-(cosA/sinA)/sinAcosA.
= sinA/sinAcos^2A - cosA/sin^2AcosA.
= 1/cos^2A - 1/sin^2A.
=sec^2A - cosec^2A.
= 1+ tan^2A - (1+cot^2A).
= 1+tan^2A - 1 - cot^2A.
= tan^2A - cot^2A.

Hence LHS= RHS PROVED.

hope it helps.
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