Math, asked by ananthakrishnan2667, 1 year ago

can't understand it please help

Attachments:

smit03: final answer 408700/4087=100
smit03: answer is 100

Answers

Answered by kavya110
0
73(73×73)+27(27×27)
———————————
73(73-1)×27(1+27)

ananthakrishnan2667: final answer plz
smit03: final answer is 100
Answered by chahatsandeep
1
using identify a^3+b^3/a^2-ab+b^2 the open the identity of a^3+b^3={a+b}{a^2-ab+b^2}/a^2-ab+b^2 then a+b only remain so 73+27=100

chahatsandeep: please mark as brainlist if you want
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