can the digit number 6 , and being a natural number, end with the digit 5? Give reason
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Prime factors of 6n=2n x 3n
For any number ending with 5 the prime factor 5 should be there in its prime factorisation (for eg: 5=5×1,15=3x5,25=5x5 , in all these 5 is a necessary prime no:) .But 6n has only 2 and 3 as prime factors So by the ununiqunesses of fundamental theorem of arithematic 6n can never end with digit 5 for any natural number n.
For any number ending with 5 the prime factor 5 should be there in its prime factorisation (for eg: 5=5×1,15=3x5,25=5x5 , in all these 5 is a necessary prime no:) .But 6n has only 2 and 3 as prime factors So by the ununiqunesses of fundamental theorem of arithematic 6n can never end with digit 5 for any natural number n.
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