Math, asked by ria7715, 1 year ago

can the following system of equations hold simultaneously?
3x+2y = 11, 2x+3y= 4, 4x-3y = 26

Answers

Answered by Vaibhavhoax
17
Heya!!

here's your answer!!!

The given equations are :

3x+2y = 11
2x+3y = 4
4x-3y = 26

Let us solve the Frist two equations.

multiplying equation (1) by 2 and equation (2) by 3, we have

6x+4y = 22
6x+9y = 12

subtracting equation (4) from equation (5), we get

5y = -10 => y = -2

substituting y = -2 in (4),

6x+4 × -2 = 22 => 6x - 8 = 22

=> 6x = 22+8 => 6x = 30 => x = 30/6 = 5.

Thus, x = 5 and y = -2 is the solution of (1) and (2). putting these values of x and y in equation (3), we have

= 4 × 5 -3 × -2 = 26

=> 20+6 => 26 = 26

Hence, the given system of three equations can hold simultaneously and the solution is
x = 5 and y = -2

Glad help you

it helps you
thank you

@vaibhavhoax
#born with attitude
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