Question

can the number 12^n and n being a natural number end with the digit 5 give reason​

Answer 1

Consider the number 6n , for n a natural number. A number ending with digit 5, must be divisible by 5. So 6 multiplied by any multiple of 5 has last digit zero.

Answer 2

no because in it's primefactorisation 12 has 2×2×3

but it does have 5so .. 12^n and n being any natural no. cant end with unit Digit being 5...