Can the number 16^n end with the digit 0 ? Give reason . Where 'n' is natural number
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if the number 16^n for any natural number n were to end with the digit zero, then it would be divisible by 5.
That is the prime factorization of 16^n would contain the prime 5.This is not possible because 16^n=(2×2×2×2)^n so the only prime in the factorization of 16^n is 2.
Hence 16^n cannot end with the digit 0 for any
natural number n.
That is the prime factorization of 16^n would contain the prime 5.This is not possible because 16^n=(2×2×2×2)^n so the only prime in the factorization of 16^n is 2.
Hence 16^n cannot end with the digit 0 for any
natural number n.
Bhupalji99:
Great, thanks friend
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