can the number 5^n ,n being a natural number, ends with the digit 0?give reason
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nope,
this is because to end a no. with zero..the factors 2 and 5 both are needed but here only 5 is there..so its not possible....it will ALWAYS end with 5 only
cheers!
this is because to end a no. with zero..the factors 2 and 5 both are needed but here only 5 is there..so its not possible....it will ALWAYS end with 5 only
cheers!
agclasher:
see
5 raise to power 0
Is 0
2 raised to power 1 is zero? lol
you have written 2 raised to power 0 is 1
which is correct but above it
If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5
It can be observed that 2 is not in the prime factorisation of 5n.
Hence, for any value of n, 5n will not be divisible by 2.
Therefore, 5n cannot end with the digit 0 for any natural number n.
It can be observed that 2 is not in the prime factorisation of 5n.
Hence, for any value of n, 5n will not be divisible by 2.
Therefore, 5n cannot end with the digit 0 for any natural number n.
eat this dude
5^0=1
Infact n^0=1
Answered by
1
Thus so
_______________________________________________________________
The number 5^n can end with digit 0
. =====. yes
. as the number 5 can be written in the form
=======. 5 ^ m * 2 ^ 0
. where 2 ^ 0 is 1
=======. The number which can be written with 2
5. As the factors it end s with digit 0 .
. Hope it helps
. all the best for exam.
_______________________________________________________________
The number 5^n can end with digit 0
. =====. yes
. as the number 5 can be written in the form
=======. 5 ^ m * 2 ^ 0
. where 2 ^ 0 is 1
=======. The number which can be written with 2
5. As the factors it end s with digit 0 .
. Hope it helps
. all the best for exam.
No it's wrong
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