Can the number 6", n being a natural number, end with the digit 5? Give reason
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Step-by-step explanation:
No it can not because as we know that the divisibility rule of 5 says that the number devided by five should end with 0 or 5 but the divisibility rule of 6^n says that the number devided by 6^n should be devided by 2^n and 3^n together.
edit: as 6^n do not satisfy the condition of 5 so it can not end with 5
Hope it helps you
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