can the number 6 n, n beginner a natural number and with the digit 5 give reason
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Answer:
6n+1,6n+2,6n+3,6n +4,6n+5
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2
Answer:
6n=2n x 3n
any number ending with 5 the prime factor V should be in the prime factorization
in all these 5 is a necessary prime number.
but 6n and has only two and three as prime factor.
so 6n can never end with five digit for any natural number n
Hope it's help
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