Question

can the number 6 n, n beginner a natural number and with the digit 5 give reason​

Answer 1

Answer:

6n+1,6n+2,6n+3,6n +4,6n+5

Answer 2

Answer:

6n=2n x 3n

any number ending with 5 the prime factor V should be in the prime factorization

in all these 5 is a necessary prime number.

but 6n and has only two and three as prime factor.

so 6n can never end with five digit for any natural number n

Hope it's help

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