Math, asked by king1557, 1 month ago

Can the number 6^n, n being a natural number, ends with a digit 0. Explain.​

Answers

Answered by kumarsinghraghav9
0

Step-by-step explanation:

it can be observed that 5 is not in the prime factorisation of 6n. Hence, for any value of n, 6n will not be divisible by 5. Therefore, 6n cannot end with the digit 0 for any natural number n.

Answered by navjotsinghddn
0

Step-by-step explanation:

It can be observed that 5 is not in the prime factorisation of 6n. Hence, for any value of n, 6n will not be divisible by 5. Therefore, 6n cannot end with the digit 0 for any natural number n.

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