can two numbeave 16 as their hcf and numbers 380 as their lcm
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Answered by
2
Hey friend, here is your answer ☺ _________________________
To find out this, we have to ensure that 16 i.e. HCF is a factor of 380 i.e. LCM.
Now see, 16 is a factor of 380 or not.
380 = 2 × 2 × 5 × 19
as u can see, 16 is not a factor 380. Therefore, any two numbers do not have 16 as their HCF and 380 as their LCM.
To find out this, we have to ensure that 16 i.e. HCF is a factor of 380 i.e. LCM.
Now see, 16 is a factor of 380 or not.
380 = 2 × 2 × 5 × 19
as u can see, 16 is not a factor 380. Therefore, any two numbers do not have 16 as their HCF and 380 as their LCM.
Answered by
4
hye
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this is a very nice question
the question is "can two numbeave 16 as their hcf and numbers 380 as their lcm?"
so for solving this sum ,we must recall a property..............
→ lcm is a mutiple of hcf ←
here , we see that 380 is not multiple of 16
∴two no. cant have 16 as their hcf and numbers 380 as their lcm
==============================================
hope it helps u........
======================================================
this is a very nice question
the question is "can two numbeave 16 as their hcf and numbers 380 as their lcm?"
so for solving this sum ,we must recall a property..............
→ lcm is a mutiple of hcf ←
here , we see that 380 is not multiple of 16
∴two no. cant have 16 as their hcf and numbers 380 as their lcm
==============================================
hope it helps u........
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