Can two numbers have 12 as their HCF and 512 their LCM? Justify your answer.
Answers
Answered by
43
512div 12 = 42.3 and it's not divide completely so the 12 as hcf and 512 as lcm for any 2 no is not possible
Answered by
39
Answer : NO
Explanation -
Given :
HCF = 12
LCM = 512
let the first number = 12x
let the second number = 12y
Product of two numbers = HCF x LCM
12x (x) 12y = 12 x 512
144xy = 6144
xy = 6144/144
xy = 42.66
Hence :
"xy" is not an exact value . So, two numbers cannot have 12 as their HCF and 512 as their LCM.
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