Can two numbers have 16 as the hcf and 280 as there lcm ? Give reasons in support of your answer
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if lcm is divisible by hcf then it is possible to have the numbers.
280 is not divisible by 16.so it is not possible
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Let the two numbers be x and y.
∴ LCM is divisible by x and y and x and y are divisible by HCF.
∴ LCM is divisible by HCF.
Given, LCM = 280 and HCF = 16
Since 16 do not divide 280.
∴ Two numbers cannot have16 as their HCF and 280 as their LCM.
∴ LCM is divisible by x and y and x and y are divisible by HCF.
∴ LCM is divisible by HCF.
Given, LCM = 280 and HCF = 16
Since 16 do not divide 280.
∴ Two numbers cannot have16 as their HCF and 280 as their LCM.
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