can two numbers have 16 as their HCF and 380 as their LCM?Give reason.
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So, for a pair of numbers, LCM must be completely divisible by the HCF of those two numbers. Therefore, if two numbers have 16 as their HCF and 380 as their LCM then, 380 must be completely divisible by 16. ... So, two numbers can't have 16 as their HCF and 380 as their LCM.
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