Can two numbers have 17 as HCF and 510 as LCM ? Why ?
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Answer:
prime factors of 92 and 510 are:
92=2*2*23
510=2*3*5*17
here we see the common factors are:
2 only so HCF(92,510)=2
Now for LCM we have to find smallest no divisible by 92 and 510 both
we have to take maximum power of all factors
so LCM=2^2*3^1*5^1*23^1*17^1
=4*3*5*23*17
=23460
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