Can two numbers have 18 as their HCF and 380 as thei LCM. Give reason?
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if you want the two numbers to be integers,then the answer is NO.
since 18 is their HCF let the two nos. be 18*a and 18*b where a and b be are some positive integers.
Since,
product of LCM and HCF = product of the two numbers
18X380 = 18aX18b
=>18ab = 380
=> 9ab =190
Since 190 is not divisible by 9,a and b be can’t have integer values. So there are no such number.
since 18 is their HCF let the two nos. be 18*a and 18*b where a and b be are some positive integers.
Since,
product of LCM and HCF = product of the two numbers
18X380 = 18aX18b
=>18ab = 380
=> 9ab =190
Since 190 is not divisible by 9,a and b be can’t have integer values. So there are no such number.
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