Can u answer this
A car weighing 2400kg and moving with a velocity of 20m/s is stopped on 10seconds by applying breaks. Calculate the retardation and regarding force.
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retardetion 2m/s force.4800N
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m is equal to 2400 kg
u is equal to 20 meter per second
v is equal to 0 as the car stops
t is equal to 10 s
v= u+ at
0= 20 + a ( 10)
a = - 2 meter per second square
F = ma
F = 2400 ×- 2
F = - 4800N
u is equal to 20 meter per second
v is equal to 0 as the car stops
t is equal to 10 s
v= u+ at
0= 20 + a ( 10)
a = - 2 meter per second square
F = ma
F = 2400 ×- 2
F = - 4800N
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