Question

can u answer this one?

Answer 1

Answer:

Total no. of outcomes     = 1,3,5,7,9,11,13,15,17,19,21,23,25,27,                                                                29,31,33,35,37,39,41,43,45,47 and 49

                                      = 25

 Favourable outcome

(a)divisible by 3=3,9,15,21,27,33,39,45,49

                         =9

Therefore,p(E) =9/25

 (b) a  composite no.  = 9,15,21,25,27,33,35,39,45 and 49

                                  =10

Therefore,p(E) = 10/25 = 2/5.

(b) not a perfect square = 3,5,7,11,13,15,17,19,21,23,27,                                      29,31,33,35,37,39,41,43,45,47

                               = 21

Therefore, P(E)       = 21 / 25

(c) multiple of 5 and 3 = 15 and 45

                                   = 2

Therefore, P(E)           =2/25