Question

can u answer this one plxzzzzz

Answer 1

the possible outcomes are (1,6)(2,3)(3,2)(6,1) and total outcomes of tossing two dice are36. thus P(E)=4/36=1/9

Answer 2

$\sf\underline{Step-by-step \: explanation}$

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(1×1=1) ; (2×1=2) ; (3×1=3) ; (4×1=4); (5×1=5);(6×1=6)

(1×2=2); (2×2=4); (3×2=6); (4×2=8); (5×2=10);(6×2=12)

(1×3=3); (2×3=6); (3×3=9); (4×3=12); (5×3=15); (6×3=18)

(1×4=4); (2×4=8); (3×4=12); (4×4=16); (5×4=20); (6×4=24)

(1×5=5); (2×5=10); (3×5=15); (4×5=20); (5×5=25) ; (6×5=30)

(1×6=6); (2×6=12); (3×6=18); (4×6=24); (5×6=30); (6×6=36)

Probability = $\frac{Number \: of \: outcomes}{Number \: of \: observations}$

Number of outcomes getting the product as 6=

4

Number of total outcomes=

36

Now are equation can be,

4/36

After cancellation...

1/9

Hence, the probability of getting 6 is,

$\dfrac{1}{9}$

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Thanks!!

#Bebrainly

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