Math, asked by Prats8967, 3 days ago

can u click the photo of this sums solving and answer (Profit,loss).​

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Answered by riyabaghel678
1

Answer:

10.Let C.P. of the bicycle = Rs.100

In the I case :

When Profit = 5% ;

S.P. = Rs. (100 + 5) = Rs. 105

In the II case:

C.P. = (100 – (30/100) × 100)

= Rs. (100 – 30) = Rs. 70

Profit = 30%

S.P. = ((100 + Profit)/100) × C.P.

= ((100 + 30)/100 ) × Rs. 70 = (130/100) × Rs. 70

= Rs. (130 × 70)/100 = Rs. 91

Difference of two selling prices = Rs. 105 – Rs. 91 = Rs. 14

If difference is Rs. 14 then C.P. of the bicycle

= Rs. 100

“ Re.1 “ = Rs. 100/14

Rs. 63 “ = Rs. (100/14) × 63

= Rs. (100 × 63)/14 = Rs. 50 × 9 = Rs. 450

11.⇒ Let the cost price of the article be Rs.100.

⇒ Given that Renu sold it at loss of 8%

⇒ Hence, The selling price =Rs.100–Rs.8=Rs.92

⇒ It is given that if she had purchased it at 10% less

⇒ The new Cost price =Rs.100−Rs.10=Rs.90.

⇒ Given that she will get a gain of 20% on it.

∴ New Selling price =Rs.90+Rs.18=Rs.108

∴ The difference in Selling price =Rs.108−Rs.92=Rs.16

⇒ Given the difference in SP = Rs 36

⇒ Initial Selling price =

16

36

×100=Rs.225

∴ The initial cost price is Rs.225.

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