Can u crack the logic?
If
1 1 1 1 = R
2 2 2 2 = T
3 3 3 3 = E
4 4 4 4 = N
Then
5 5 5 5 = ?
Answers
Step-by-step explanation:
The Q has two pattern. Its not a perfect Q. It can be asked in exam only if Options are given. Otherwise it would become incorrect Q as it has two patterns and Q can be disputed if asked without options.
First pattern:
Sum of every digit- write it down in word.
5+5+5+5=20 write it in word
Twenty. So if u follow this pattern answer is "Y"
2nd pattern:
Find out the "Digital Root"
1+1+1+1=4. 4 is the Digital Root. Write it down in word - FOUR
2+2+2+2=8. 8 is digital root. EIGHT
3+3+3+3=12. 12=1+2=3. THREE
4+4+4+4=16. 16=7. SEVEN
HENCE
5+5+5+5=20. 20=2+0=2. TWO
As per 2nd pattern answer is "O"
This Q cannot be asked without options.
Even if options are given and both "Y" and "O" are given, then we can dispute the Q. If options have only one of "Y" or "O"
Then Q is correct.
However…
I would choose "Y" as answer if both are in option. Bcz of another pattern.
In first pattern:
Four
Eight
Twelve
Sixteen
Twenty
The answers in every line also follow a pattern.
4---8---12---16---20
Adding 4 consecutively.
So i would choose "Y" for safe side.
Answer:
ɪɴ ᴛʜɪꜱ ᴩᴀᴛᴛᴇʀɴ :
1+1+1+1=> 4 => ꜰᴏᴜʀ => ʀ.
2+2+2+2=>8=> ᴇɪɢʜᴛ=> ᴛ.
3+3+3+3=>12=> ᴛᴡᴇʟᴠᴇ=> ᴇ.
4+4+4+4=> 16=>ꜱɪxᴛᴇᴇɴ=>ɴ.
ɴᴏᴡ ᴡᴇ ꜰɪɴᴅ 5 5 5 5 :;:;:;;:
5+5+5+5=> 20=> ᴛᴡᴇᴇᴛy =>y.
ꜱᴏʟᴠᴇᴅ