can u do this question 24
fast
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Answered by
1
as given: for the first km, the fare is the only Rs.8 and for latter kms, it is Rs5/km
so equation is: y = 8 + (x-1)5
y = 8 + 5x - 5
y = 3 + 5x
given: y= 63
63 = 3 + 5x; 60 = 5x ; x = 12
therefore, the traveler had travelled 12 kms ;)
so equation is: y = 8 + (x-1)5
y = 8 + 5x - 5
y = 3 + 5x
given: y= 63
63 = 3 + 5x; 60 = 5x ; x = 12
therefore, the traveler had travelled 12 kms ;)
Answered by
2
Let the total distance travelled be x km.
For (x-1) km, fare is 5 per km.
Let the fare be y.
y = 8 + 5(x-1)
y= 8+ 5x -5
Therefore,
y = 5x + 3
When cost = y = RS.63,
Therefore,
63 = 5x + 3
5x = 60,
x = 12.
Therefore the distance travelled is 12 km
Please mark as Brainliest to gain some points yourself
For (x-1) km, fare is 5 per km.
Let the fare be y.
y = 8 + 5(x-1)
y= 8+ 5x -5
Therefore,
y = 5x + 3
When cost = y = RS.63,
Therefore,
63 = 5x + 3
5x = 60,
x = 12.
Therefore the distance travelled is 12 km
Please mark as Brainliest to gain some points yourself
sahil0073:
oooooo its so much bigger
actually I have posted it considering it is a 4 mark question
If you write short answer, you willget 1-2 marks at the most..
so what? at least it is correct!!
i an not saying that it is wrong
i m not commenting on your statement...mine were to sahil
your answer is correct too but it will not getch you complete 4 marks in any exam. There ate marks for steps as well
oh, all right
i don't need to memorise steps... i m in 10th ;)
thank to both
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