Question

Can u explain this question's ever step - the vapour density of a gas is 11.2. The volume occupied by 11.2 g of the gas at STP will be??

Answer 1

Atomic mass of an element = 2 * Vapour density

So, atomic mass = 2*11.2 = 22.4 u

Now,
Volume occupied by a gas at STP = 22.4 litres

Now, no of moles = Given Mass / Atomic mass
= 11.2 / 22.4
= 0.5 moles

Therefore,
No.of moles of the gas = 0.5

Also, we know that
No.of moles of a gas = volume of gas / Volume at STP
So,
0.5 = Volume of gas / 22.4
Volume of gas = 11.2 litres.

Therefore,
11.2 grams of the given gas at STP occupies around 11.2 Litres.

Answer 2

At stp each and every gas has 22L as its volume.And it always remains same