Question

Can u give an example pls.

I will report if I don’t get a proper answer

Answer 1

Answer:

universal law of gravitation formula it is

Explanation:

take two bodies of mass 10g and 20g

then dist. around them is 2 cm so 2^2=4

now 200/4×6.721 as g

now calculate...........

Answer 2

☞ $\:{\bf{\underline{\purple{Law \:of Gravitation}}}}$

• ${\boxed{\bf {F = G\dfrac{Mm }{ r^2} }}}$

☞ $\:{\bf{\underline{\purple{What \: is \: Law \:of Gravitation}}}}$

• Law of gravity is states that every $\bold{object }$ attracts every $\bold{other\:object}$ with a $\bold{force}$ of any $\bold{2 \: objects}$ is directly $\bold{proportional}$ to the $\bold{mass}$ of each object.

$\boxed{</p><p></p><p>\begin{minipage}{6 cm} \\\\</p><p></p><p>\:{\bf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:F = G\dfrac{Mm }{ r^2}}} \\ \\</p><p></p><p>\sf{\:\:\:\:Where,}\\\\</p><p></p><p>\sf{\:\:\bullet\:\:{\bf{F}}\: \:=\: Gravitation}\\\\</p><p>\sf{\:\:\bullet\:\:{\bf{M\:\& \: m}}\:\: = \:masses \: of \: two \: objects}\\\\</p><p></p><p>\sf{\:\:\bullet\:\:{\bf{r}}\: \:= \: separation \: between \: objects} \\\\</p><p>\sf{\:\:\bullet\:\:{\bf{G}}\:\: = \: universal \: gravitational\: constant}\\ </p><p></p><p>\end{minipage}</p><p></p><p>}$

☞ $\:{\bf{\underline{\purple{Example \: Problem}}}}$

★ Now, Let's use Newton's universal law of gravitation to calculate the gravitational force on earth

$\dashrightarrow\:\: \sf{F = G\dfrac{m_{1}m_{2} }{ r^2}}$

$\dashrightarrow\:\: \sf{F = 6.67 \times 10^{-11} \dfrac{5.98 \times 10^{24}m_{2}}{(6.37 \times 10^{6})^{2}}}$

$\dashrightarrow\:\: \sf{F = 9.8\:m_{2}}$