Question

Can u guys answer question 2

Answer 1

$x - a = 0$

$x = a$

${x}^{3} - a {x}^{2} + 6x - a$

putting x=a in given equation

${a}^{3} - a( {a}^{2} ) + 6a - a$

${a}^{3} - {a}^{3} + 6a - a$

$6a - a$

$hence \: the \: remainder \: is \: 5a$

hope it helps

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