Question

Can u guys answer question 6 (ii) and (iii)

Answer 1

Answer:

2) we can use, (x+a)(x+b)=$x^{2}$+(a+b)x+ab

(3x+4)(3x-5)

=$9x^{2}$+(4-5)x+4*-5

=$9x^{2}$-x-20

3) we can use,$(a+b+c)^{2}$=$a^{2}$+$b^{2}$+$c^{2}$+2ab+2bc+2ca

$(-3a+5b+4c)^{2}$

=$9a^{2}$+$25b^{2}$+$16c^{2}$-30ab+40bc-24ac

Step-by-step explanation:

hope it helps.....

Answer 2

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answer is attached-6