Can u guys answer the 21 question
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Radius of roller = 1.5 m
Length of roller = 2.5 m
Curved Surface Area of roller = 2 pi r h
= 2 × 22 × 1.5 × 2.5 / 7
= 22 × 1.5 × 5 / 7
= 33 × 5 / 7
= 165 / 7 m^2
Area covered in 1 revolution = 165/ 7 m^2
Number of revolution = Total Area covered / Area covered in one revolution
= 16500 ÷ 165 / 7
= 16500 × 7 / 165
= 100 × 7
= 700
Number of revolution = 700
Length of roller = 2.5 m
Curved Surface Area of roller = 2 pi r h
= 2 × 22 × 1.5 × 2.5 / 7
= 22 × 1.5 × 5 / 7
= 33 × 5 / 7
= 165 / 7 m^2
Area covered in 1 revolution = 165/ 7 m^2
Number of revolution = Total Area covered / Area covered in one revolution
= 16500 ÷ 165 / 7
= 16500 × 7 / 165
= 100 × 7
= 700
Number of revolution = 700
Answered by
3
Given the length of a cylindrical roller = 2.5m.
Given radius of the cylindrical roller = 1.5m.
We know that curved surface area of the roller = 2pirh
= 2 * 22/7 * 1.5 * 2.5
= 44 * 3.75/7
= 165/7.
= 23.571m^2
Given total area covered = 16500m^2.
Therefore the total number of revolutions = 16500/23.571
= 700.
Hope this helps!
Given radius of the cylindrical roller = 1.5m.
We know that curved surface area of the roller = 2pirh
= 2 * 22/7 * 1.5 * 2.5
= 44 * 3.75/7
= 165/7.
= 23.571m^2
Given total area covered = 16500m^2.
Therefore the total number of revolutions = 16500/23.571
= 700.
Hope this helps!
siddhartharao77:
:-)
Tysm
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