Can u please answer the 8th & the 9th one.
Stepwise please.
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Hiiiii..
● In 8 question .....
CH4 ----> C + 2 H2 ....
Now given that 452 kg of metane given ....
By mole - mole analysis uu can find amount of C and H easily ....
formula : mole of CH4 /1 = mole of C / 1 ...
As 1 is stichiometric coefficient...
Amount of C = 339 kg
Amount of H2 = 113 kg .....
● In 9 question ....
2 H2O2 ----> 2 H2O + O2 ....
H2O2 is hydrogen peroxide ....
In 1 hr. H2O2 produced is 3.4 kg ....
Amount of O2 = 3.4 × 32 / 2 × 34 ...
= 1.6 Kg ...
So in 10 hr. It is = 1.6 × 10 = 16 kg .....
I hope u got it....☺☺☺
● In 8 question .....
CH4 ----> C + 2 H2 ....
Now given that 452 kg of metane given ....
By mole - mole analysis uu can find amount of C and H easily ....
formula : mole of CH4 /1 = mole of C / 1 ...
As 1 is stichiometric coefficient...
Amount of C = 339 kg
Amount of H2 = 113 kg .....
● In 9 question ....
2 H2O2 ----> 2 H2O + O2 ....
H2O2 is hydrogen peroxide ....
In 1 hr. H2O2 produced is 3.4 kg ....
Amount of O2 = 3.4 × 32 / 2 × 34 ...
= 1.6 Kg ...
So in 10 hr. It is = 1.6 × 10 = 16 kg .....
I hope u got it....☺☺☺
GB2010:
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k let someone also answer
now mark me as a brainlist...
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if u feel something wrong then u should discuss with me.... it's totally wrong to leave a person who treat u as a friend and whom u called a friend.... I know we talk very little but I think this little conversation is worthful but today I saw our all texts r deleted by you..... I really disappointed rosy..... before going I tell u onething don't made any relation if u r not interested to continue it..... because it really hurt others sentiments....
I hope you don't do this with ur other friends also....tcr... have a blessed life...
Answered by
0
answer is 16kg
O2=3.4×32/34×2=1.6kg
1.6×10=16kg
O2=3.4×32/34×2=1.6kg
1.6×10=16kg
i want stepd
amount of O2=1.6kg
sorry
3.4kg
ok
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