Question

Can u please find the answer for this question?​

Answer 1

Answer:

Draw BL⊥PQ and CM⊥RS. As PQ∥RS, so, BL∥CM.

The alternate interior angles are equal, so,

∠LBC=∠MCB                         (1)

It is known that the angle of reflection is equal to the angle of incidence, therefore,

∠ABL=∠LBC                          (2)

And,

∠MCB=∠MCD                        (3)

From equation (1), (2) and (3),

∠ABL=∠MCD                         (4)

Add equation (1) and (4),

∠LBC+∠ABL=∠MCB+∠MCD

∠ABC=∠BCD

Since, these are the interior angles and are equal, hence, AB∥CD.