can u please tell me the solution of this question 39
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Q. Factorize 6√3 x² - 47 x + 5 √3.
Solution : 6√3 x² - 47 x + 5 √3
= 6√3 x² - 45 x - 2 x + 5√3
= 3√3 x ( 2 x - 5√3 ) - 1 ( 2 x - 5√3 )
= ( 2 x - 5√3 ) ( 3√3 x - 1 ).
♦ Steps to solve a quadratics equation by splitting middle term.
• Middle term should be broken in such a way that its sum should be equal to middle term and its product should be equal to product of first term and last term.
• After that you will get 4 terms, from first 2 term take common and from 3rd and 4th term take common.
•Now you will find terms in such a way : a x ( b x + c ) + m ( b x + c ).
•Now take ( b x + c ) as common .Then you will find like this ( b x + c ) ( a x + m).
Note : The ' x ' is variable in above steps.
☺☺☺
Q. Factorize 6√3 x² - 47 x + 5 √3.
Solution : 6√3 x² - 47 x + 5 √3
= 6√3 x² - 45 x - 2 x + 5√3
= 3√3 x ( 2 x - 5√3 ) - 1 ( 2 x - 5√3 )
= ( 2 x - 5√3 ) ( 3√3 x - 1 ).
♦ Steps to solve a quadratics equation by splitting middle term.
• Middle term should be broken in such a way that its sum should be equal to middle term and its product should be equal to product of first term and last term.
• After that you will get 4 terms, from first 2 term take common and from 3rd and 4th term take common.
•Now you will find terms in such a way : a x ( b x + c ) + m ( b x + c ).
•Now take ( b x + c ) as common .Then you will find like this ( b x + c ) ( a x + m).
Note : The ' x ' is variable in above steps.
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bubblepupnp:
thank u so much
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