Math, asked by mia080819, 9 months ago

Can u pls. Solve the first question

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Answered by UMASK
1

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In Polygon MNOPQR

MP=9 cm

MD=7 cm

DP=MP-MD=9-7=2 cm

MC=6 cm

CD=MD-MC=7-6=1 cm

CP=CD+DP=1+2=3 cm

MB=4 cm

BC=MC-MB=6-4=2 cm

MA=2 cm

AB=MB-MA=4-2=2 cm

NA=2.5 cm

OC=3 cm

QD=2 cm

RB=2.5 cm

AC=AB+BC=2+2=4 cm

BD=BC+CD=2+1=3 cm

Area of triangle=1/2xbxh

Area of trapezium=1/2(sum of parallel sides)xheight

Area of Polygon MNOPQR=ar(MAN)+ar of trapezium(ACON)+ar(OCP)+ar(MBR)+ar of trapezium(BRQD)+ar(QDP)

Area of Polygon MNOPQR=

1/2(2)(2.5)+1/2(2.5+3)(4)+1/2(3)(3)+1/2(4)(2.5)+1/2(2.5+2)(3)+1/2(2)(2)

Area of Polygon MNOPQR=2.5+11+4.5+5+6.75+2=31.75 square cm

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