Question

can u plz ansr this qstn......​

Answer 1

Answer:

8400 cm2 = 0.84 m2 in this question

Answer 2

GIVEN :-

• area of cross section of pipe is 3.5cm²
• water is flowing out of pipe at the rate of 40 cm/s.

TO FIND :-

• amount of water flowed in one minute

SOLUTION :-

SO FOR AMOUNT OF WATER FLOWED OUT OF THE PIPE IN ONE MINUTE WE HAVE TO CALCULATE THE RATE OF FLOW

$\bold{rate \: of \: flow \: = area \: of \: cross \: section } \\ \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \times \: rate \: of \: water \: }$

NOW RATE OF FLOW :-

$\implies \: \rm{ \: 3.5 \:cm^{2} \times 40 \: cm \:/ second}$

[ NOTE ! THAT WE ALSO MULTIPLY THE UNITS OF THE MAGNITUDE I.E :- cm² × cm/second = cm³/second ]

$\implies \: \rm{ 1 40 \: cm ^{3} \:/ second}$

$\implies \boxed{ \rm{ \: rate \: of \: flow \: = 140 {cm}^{3} / second}}$

NOW WE HAVE TO FIND RATE OF FLOW IN ONE MINUTE

[ NOTE ! THAT RATE OF FLOW IS IN SECOND SO WE WILL CONVERT MINUTES IN SECOND SO THE UNITS WILL REMAIN SAME ]

• TAKING 1 MINUTE = 60 SECONDS (1 MINUTE = 60 SECONDS)

AMOUNT OF WATER FLOWED IN ONE MINUTE :-

$\bf{ \: water \: flowed \: in \: one \: min \: = } \\ \\ \bf{rate \: of \: flow \: \times given \: time}$

$\implies \: \rm{ \: 140 {cm}^{3} \: \: </u></strong><strong><u>/</u></strong><strong><u>second \: \times 60 \: \: </u></strong><strong><u> second } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm{= 8400 {cm}^{3} }$

$\implies$

$\: \: \: \: \: \: \: \: \: \boxed{ \boxed{ \rm{water \: flowed \: in \: 1 \: min =8400 {cm}^{3} }}}$

OTHER INFORMATION :-

FLOW RATE FORMULA :

• The flow rate of a liquid is a measure of the volume of liquid that moves in a certain amount of time. The flow rate depends on the area of the pipe or channel that the liquid is moving through, and the velocity of the liquid.

• If the liquid is flowing through a pipe, the area is A = πr², where r is the radius of the pipe. For a rectangle, the area is A = w×h where w is the width, and h is the height.

• The flow rate can be measured in meters cubed per second (m³/s), or in liters per second (L/s). Liters are more common for measures of liquid volume, and 1 m³/s = 1000 L/s.

fluid flow rate = area of the pipe or channel×velocity of the liquid

• Q = Av

• Q = AvQ = liquid flow rate (m³/s or L/s)

• Q = AvQ = liquid flow rate (m³/s or L/s)A = area of the pipe or channel (m²)

• V = velocity of the liquid (m/s)