Question

can u plz answer the attachment below

Answer 1

Answer:

(i) Three pair of equal parts are:

AB=AC (Equal Side)

<BAD=<CAD (Equal Angle)

AD=AD (Height)

(ii) Yes, ∆ADB≅∆ADC, from SAS Criteria.

(iii) As ∆ADB≅∆ADC.

So, <B=<C (c.p.c.t.)- Corresponding Part of Congruent Triangles.

Hope you get this!!

Answer 2

Step-by-step explanation:

2) yes ,∆ADB is congruent to ∆ADC

Reson:

In ∆ADB and ∆ADC

AB = AC (Given)

AD =DA (Common side to both triangle)

<BAD = <DAC (Bisector ,so they are each 90*)

Hence we can conclude that ∆ADB is congruent to ∆ADC (SAS Congruence)

3) If ∆ADB is congruent to ∆ADC,

Then by CPCT we can conclude that

<B = <C

Hope it helped....if satisfied pls mark me brainliest