Question

Can u plz help me doing all these sums!plzzz

Answer 1

ʜᴏᴩᴇ ɪᴛ ʜᴇʟᴩꜱ yᴏᴜ :)(:

Answer 2

${x}^{2} - \frac{1}{9} \\ = {x}^{2} - {( \frac{1}{3}) }^{2} \\ (x - \frac{1}{3} )(x + \frac{1}{3} )$



$\frac{4}{25} {m}^{2} - 64 \\ = { (\frac{2}{5}m) }^{2} - {8}^{2} \\ = ( \frac{2}{5} m - 8)( \frac{2}{5} m + 8)$




$\frac{ {x}^{2} }{9} - \frac{ {y}^{2} }{4} \\ = {( \frac{x}{3} )}^{2} - {( \frac{y}{2}) }^{2} \\ = ( \frac{x}{3} - \frac{y}{2} ) ( \frac{x}{3} + \frac{y}{2} )$



$\frac{36}{ {a}^{2} } - \frac{25}{ {b}^{2} } \\ = { (\frac{6}{a}) }^{2} - {( \frac{5}{b}) }^{2} \\ = ( \frac{6}{a} - \frac{5}{b} )( \frac{6}{a} + \frac{5}{b} )$